Armstrong number program in c

Armstrong Number

Problem Statement

Write a c program to check whether the given number is an Armstrong number or not.

Solution

#include<stdio.h>

int main()

{

int n,temp,a,b=0;

scanf("%d",&n);

temp=n;

while(n!=0)

{

a=n%10;

b=b+(a*a*a);

n=n/10;

}

if(temp==b)

{

printf("%d is an Armstrong Number",temp);

}

else

{

printf("%d is not an Armstrong Number",temp);

}

return 0;

}

Input

153

Output

153 is an Armstrong Number

Output Explanation

153 ->( 1(cube)+5(cube)+3(cube))

153->(1+125+27)

153->(153)

It matches with input given number. So It is an Armstrong Number.

Input 2

275

Output 2

275 is not an Armstrong Number

Program Explanation

In this Armstrong number c program, we have declared integer variables n, temp, a and b.
Using n variable getting the input using scanf function.
after getting input stored in another variable known as temp to check given number is Armstrong number or not.
After that in while loop convert the input number into digits.
Each time during conversion cube the digits and add with the b values, continue the process of digit conversion operation till the input number tends to zero.
we are checking the temp and b variable values for verification of Armstrong number in this c program.
If both are same then the given number is an Armstrong number or else the given number is not an Armstrong number.
The final Output is displayed using printf function in this program.